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Fix GH-1181: Incorrect example for IntlDateFormatter::setPattern()

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In addition to fixing the format specifiers, we also echo line breaks,
so the output matches the example code.
This commit is contained in:
Christoph M. Becker
2021-12-08 11:23:17 +01:00
parent d09a881a8e
commit 2790c0fd69
1 changed files with 18 additions and 20 deletions
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38
reference/intl/dateformatter/set-pattern.xml
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@@ -77,12 +77,11 @@ $fmt = datefmt_create(
IntlDateFormatter::GREGORIAN,
'MM/dd/yyyy'
);
echo 'pattern of the formatter is : ' . datefmt_get_pattern($fmt);
echo 'First Formatted output with pattern is ' . datefmt_format($fmt, 0);
datefmt_set_pattern($fmt, 'yyyymmdd hh:mm:ss z');
echo 'Now pattern of the formatter is : ' . datefmt_get_pattern($fmt);
echo 'Second Formatted output with pattern is ' . datefmt_format($fmt, 0);
echo 'Pattern of the formatter is : ', datefmt_get_pattern($fmt), PHP_EOL;
echo 'First Formatted output with pattern is ', datefmt_format($fmt, 0), PHP_EOL;
datefmt_set_pattern($fmt, 'yyyyMMdd hh:mm:ss z');
echo 'Now pattern of the formatter is : ', datefmt_get_pattern($fmt), PHP_EOL;
echo 'Second Formatted output with pattern is ', datefmt_format($fmt, 0), PHP_EOL;
?>
]]>
</programlisting>
@@ -99,25 +98,24 @@ $fmt = new IntlDateFormatter(
IntlDateFormatter::GREGORIAN,
'MM/dd/yyyy'
);
echo 'pattern of the formatter is : ' . $fmt->getPattern();
echo 'First Formatted output is ' . $fmt->format(0);
$fmt->setPattern('yyyymmdd hh:mm:ss z');
echo 'Now pattern of the formatter is : ' . $fmt->getPattern();
echo 'Second Formatted output is ' . $fmt->format(0);
echo 'Pattern of the formatter is : ', $fmt->getPattern(), PHP_EOL;
echo 'First Formatted output is ', $fmt->format(0), PHP_EOL;
$fmt->setPattern('yyyyMMdd hh:mm:ss z');
echo 'Now pattern of the formatter is : ', $fmt->getPattern(), PHP_EOL;
echo 'Second Formatted output is ', $fmt->format(0), PHP_EOL;
?>
]]>
</programlisting>
</example>
&example.outputs;
<screen>
<![CDATA[
pattern of the formatter is : MM/dd/yyyy
First Formatted output with pattern is 12/31/1969
Now pattern of the formatter is : yyyymmdd hh:mm:ss z
Second Formatted output with pattern is 19690031 04:00:00 PST
&example.outputs;
<screen>
<![CDATA[
Pattern of the formatter is : MM/dd/yyyy
First Formatted output is 12/31/1969
Now pattern of the formatter is : yyyyMMdd hh:mm:ss z
Second Formatted output is 19691231 04:00:00 PST
]]>
</screen>
</screen>
</refsect1>
<refsect1 role="seealso">