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PHP requires integer typehints to be written "int" and does not allow "integer" as an alias. This changes type error messages to match the actual type name and avoids confusing messages like "must be of the type integer, integer given".
32 lines
752 B
PHP
32 lines
752 B
PHP
--TEST--
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ibase_drop_db(): Basic test
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--SKIPIF--
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<?php include("skipif.inc"); ?>
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--FILE--
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<?php
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require("interbase.inc");
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unlink($file = tempnam('/tmp',"php_ibase_test"));
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$db = ibase_query(IBASE_CREATE,
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sprintf("CREATE SCHEMA '%s' USER '%s' PASSWORD '%s' DEFAULT CHARACTER SET %s",$file,
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$user, $password, ($charset = ini_get('ibase.default_charset')) ? $charset : 'NONE'));
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var_dump($db);
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var_dump(ibase_drop_db($db));
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var_dump(ibase_drop_db(1));
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var_dump(ibase_drop_db(NULL));
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?>
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--EXPECTF--
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resource(%d) of type (Firebird/InterBase link)
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bool(true)
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Warning: ibase_drop_db() expects parameter 1 to be resource, int given in %s on line %d
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NULL
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Warning: ibase_drop_db() expects parameter 1 to be resource, null given in %s on line %d
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NULL
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