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187 lines
6.4 KiB
C
187 lines
6.4 KiB
C
/*
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-------------------------------------------------------------------------------
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lookup3.c, by Bob Jenkins, May 2006, Public Domain.
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*/
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#ifndef _MSC_VER
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#include <sys/param.h> /* attempt to define endianness */
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#endif
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#ifdef linux
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# include <endian.h> /* attempt to define endianness */
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#endif
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#include "hash_function.h"
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#define hashsize(n) ((uint32_t)1<<(n))
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#define hashmask(n) (hashsize(n)-1)
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#define rot(x,k) (((x)<<(k)) | ((x)>>(32-(k))))
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/*
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-------------------------------------------------------------------------------
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mix -- mix 3 32-bit values reversibly.
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This is reversible, so any information in (a,b,c) before mix() is
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still in (a,b,c) after mix().
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If four pairs of (a,b,c) inputs are run through mix(), or through
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mix() in reverse, there are at least 32 bits of the output that
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are sometimes the same for one pair and different for another pair.
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This was tested for:
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* pairs that differed by one bit, by two bits, in any combination
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of top bits of (a,b,c), or in any combination of bottom bits of
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(a,b,c).
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* "differ" is defined as +, -, ^, or ~^. For + and -, I transformed
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the output delta to a Gray code (a^(a>>1)) so a string of 1's (as
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is commonly produced by subtraction) look like a single 1-bit
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difference.
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* the base values were pseudorandom, all zero but one bit set, or
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all zero plus a counter that starts at zero.
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Some k values for my "a-=c; a^=rot(c,k); c+=b;" arrangement that
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satisfy this are
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4 6 8 16 19 4
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9 15 3 18 27 15
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14 9 3 7 17 3
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Well, "9 15 3 18 27 15" didn't quite get 32 bits diffing
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for "differ" defined as + with a one-bit base and a two-bit delta. I
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used http://burtleburtle.net/bob/hash/avalanche.html to choose
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the operations, constants, and arrangements of the variables.
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This does not achieve avalanche. There are input bits of (a,b,c)
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that fail to affect some output bits of (a,b,c), especially of a. The
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most thoroughly mixed value is c, but it doesn't really even achieve
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avalanche in c.
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This allows some parallelism. Read-after-writes are good at doubling
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the number of bits affected, so the goal of mixing pulls in the opposite
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direction as the goal of parallelism. I did what I could. Rotates
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seem to cost as much as shifts on every machine I could lay my hands
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on, and rotates are much kinder to the top and bottom bits, so I used
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rotates.
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-------------------------------------------------------------------------------
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*/
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#define mix(a,b,c) \
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{ \
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a -= c; a ^= rot(c, 4); c += b; \
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b -= a; b ^= rot(a, 6); a += c; \
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c -= b; c ^= rot(b, 8); b += a; \
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a -= c; a ^= rot(c,16); c += b; \
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b -= a; b ^= rot(a,19); a += c; \
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c -= b; c ^= rot(b, 4); b += a; \
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}
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/*
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-------------------------------------------------------------------------------
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final -- final mixing of 3 32-bit values (a,b,c) into c
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Pairs of (a,b,c) values differing in only a few bits will usually
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produce values of c that look totally different. This was tested for
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* pairs that differed by one bit, by two bits, in any combination
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of top bits of (a,b,c), or in any combination of bottom bits of
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(a,b,c).
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* "differ" is defined as +, -, ^, or ~^. For + and -, I transformed
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the output delta to a Gray code (a^(a>>1)) so a string of 1's (as
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is commonly produced by subtraction) look like a single 1-bit
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difference.
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* the base values were pseudorandom, all zero but one bit set, or
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all zero plus a counter that starts at zero.
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These constants passed:
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14 11 25 16 4 14 24
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12 14 25 16 4 14 24
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and these came close:
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4 8 15 26 3 22 24
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10 8 15 26 3 22 24
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11 8 15 26 3 22 24
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-------------------------------------------------------------------------------
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*/
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#define final(a,b,c) \
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{ \
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c ^= b; c -= rot(b,14); \
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a ^= c; a -= rot(c,11); \
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b ^= a; b -= rot(a,25); \
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c ^= b; c -= rot(b,16); \
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a ^= c; a -= rot(c,4); \
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b ^= a; b -= rot(a,14); \
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c ^= b; c -= rot(b,24); \
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}
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/*
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-------------------------------------------------------------------------------
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hashlittle() -- hash a variable-length key into a 32-bit value
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k : the key (the unaligned variable-length array of bytes)
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length : the length of the key, counting by bytes
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initval : can be any 4-byte value
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Returns a 32-bit value. Every bit of the key affects every bit of
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the return value. Two keys differing by one or two bits will have
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totally different hash values.
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The best hash table sizes are powers of 2. There is no need to do
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mod a prime (mod is sooo slow!). If you need less than 32 bits,
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use a bitmask. For example, if you need only 10 bits, do
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h = (h & hashmask(10));
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In which case, the hash table should have hashsize(10) elements.
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If you are hashing n strings (uint8_t **)k, do it like this:
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for (i=0, h=0; i<n; ++i) h = hashlittle( k[i], len[i], h);
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By Bob Jenkins, 2006. bob_jenkins@burtleburtle.net. You may use this
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code any way you wish, private, educational, or commercial. It's free.
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Use for hash table lookup, or anything where one collision in 2^^32 is
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acceptable. Do NOT use for cryptographic purposes.
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-------------------------------------------------------------------------------
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*/
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uint32_t hash_function( const void *key, size_t length, uint32_t initval)
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{
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uint32_t a,b,c; /* internal state */
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const uint8_t *k = (const uint8_t *)key;
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/* Set up the internal state */
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a = b = c = 0xdeadbeef + ((uint32_t)length) + initval;
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/*--------------- all but the last block: affect some 32 bits of (a,b,c) */
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while (length > 12)
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{
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a += k[0];
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a += ((uint32_t)k[1])<<8;
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a += ((uint32_t)k[2])<<16;
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a += ((uint32_t)k[3])<<24;
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b += k[4];
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b += ((uint32_t)k[5])<<8;
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b += ((uint32_t)k[6])<<16;
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b += ((uint32_t)k[7])<<24;
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c += k[8];
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c += ((uint32_t)k[9])<<8;
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c += ((uint32_t)k[10])<<16;
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c += ((uint32_t)k[11])<<24;
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mix(a,b,c);
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length -= 12;
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k += 12;
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}
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/*-------------------------------- last block: affect all 32 bits of (c) */
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switch(length) /* all the case statements fall through */
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{
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case 12: c+=((uint32_t)k[11])<<24;
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case 11: c+=((uint32_t)k[10])<<16;
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case 10: c+=((uint32_t)k[9])<<8;
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case 9 : c+=k[8];
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case 8 : b+=((uint32_t)k[7])<<24;
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case 7 : b+=((uint32_t)k[6])<<16;
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case 6 : b+=((uint32_t)k[5])<<8;
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case 5 : b+=k[4];
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case 4 : a+=((uint32_t)k[3])<<24;
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case 3 : a+=((uint32_t)k[2])<<16;
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case 2 : a+=((uint32_t)k[1])<<8;
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case 1 : a+=k[0];
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break;
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case 0 : return c;
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}
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final(a,b,c);
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return c;
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}
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